27.11.2014 | Exam 1

[_Hofi_]

Here's the first exam from 2014.

[Chris]

Is it the exam which is usually taken at the end of the semester? Or is it one of the those which is taken during the semster (Angabe eines übungstests)?

regards christoph

[clstn_d]

Did anyone find how to solve the question 6 with the lumped muscle because I have no idea how to start ?
Thanks for you help !

[reox]

Did anyone find how to solve the question 6 with the lumped muscle because I have no idea how to start ?
Thanks for you help !

Without calculation anything but I would first calculate the differential equations for a single Box (alike the one in the tutorial 2). The force of two boxes combined is the sum of them and you calculate for (Only Box1 is active) and for (Box 1 + Box 2). In both cases you have Boundary Conditions you can put in. BTW: due to isometric conditions.

[MComenda]

But in the second part (box 1 + box 2), do you consider T=T/2? Because now T is holding the boxes..

[reox]

But in the second part (box 1 + box 2), do you consider T=T/2? Because now T is holding the boxes..

As far as I understood the question, the activation of box 1 is not changed after 0.8C. only the second box activates too. T is the output tension of the whole system, imo. So T is not holding the boxes, i think, but rather T is produced by both boxes combined?

[MComenda]

Hum ok, so for the second part when you write the equation of equilibrium you say that T is equal to the sum of all elements in the two boxes?
Sorry about all these questions, but I am really confused

[reox]

Hum ok, so for the second part when you write the equation of equilibrium you say that T is equal to the sum of all elements in the two boxes?
Sorry about all these questions, but I am really confused

Yes I would do it like this (but i have no idea if this is correct either )
I think you can also say that T is the sum of the T's of each boxes the whole time, but for 0 ... 0.8C T_2 is 0.