27.11.2014 | Exam 1

Antworten
Benutzeravatar
_Hofi_
Beiträge: 24
Registriert: 29.01.2015, 19:04

27.11.2014 | Exam 1

Beitrag von _Hofi_ » 13.11.2016, 15:35

Here's the first exam from 2014.
Du hast keine ausreichende Berechtigung, um die Dateianhänge dieses Beitrags anzusehen.

Chris
Beiträge: 3
Registriert: 13.10.2016, 14:09

Re: 27.11.2014 | Exam 1

Beitrag von Chris » 14.11.2016, 15:26

Is it the exam which is usually taken at the end of the semester? Or is it one of the those which is taken during the semster (Angabe eines übungstests)?

regards christoph

clstn_d
Beiträge: 2
Registriert: 20.11.2016, 22:26

Re: 27.11.2014 | Exam 1

Beitrag von clstn_d » 22.11.2016, 17:05

Did anyone find how to solve the question 6 with the lumped muscle because I have no idea how to start ?
Thanks for you help !

reox
Beiträge: 14
Registriert: 30.11.2015, 20:46

Re: 27.11.2014 | Exam 1

Beitrag von reox » 22.11.2016, 22:58

clstn_d hat geschrieben:Did anyone find how to solve the question 6 with the lumped muscle because I have no idea how to start ?
Thanks for you help !
Without calculation anything but I would first calculate the differential equations for a single Box (alike the one in the tutorial 2). The force of two boxes combined is the sum of them and you calculate for 0 \leq t \lt 0.8C (Only Box1 is active) and for 0.8C \leq t \leq C (Box 1 + Box 2). In both cases you have Boundary Conditions you can put in. BTW: x = const. due to isometric conditions.

MComenda
Beiträge: 2
Registriert: 17.11.2016, 20:28

Re: 27.11.2014 | Exam 1

Beitrag von MComenda » 23.11.2016, 10:27

But in the second part (box 1 + box 2), do you consider T=T/2? Because now T is holding the boxes..

reox
Beiträge: 14
Registriert: 30.11.2015, 20:46

Re: 27.11.2014 | Exam 1

Beitrag von reox » 23.11.2016, 11:10

MComenda hat geschrieben:But in the second part (box 1 + box 2), do you consider T=T/2? Because now T is holding the boxes..
As far as I understood the question, the activation of box 1 is not changed after 0.8C. only the second box activates too. T is the output tension of the whole system, imo. So T is not holding the boxes, i think, but rather T is produced by both boxes combined?

MComenda
Beiträge: 2
Registriert: 17.11.2016, 20:28

Re: 27.11.2014 | Exam 1

Beitrag von MComenda » 23.11.2016, 11:25

Hum ok, so for the second part when you write the equation of equilibrium you say that T is equal to the sum of all elements in the two boxes?
Sorry about all these questions, but I am really confused :)

reox
Beiträge: 14
Registriert: 30.11.2015, 20:46

Re: 27.11.2014 | Exam 1

Beitrag von reox » 23.11.2016, 12:07

MComenda hat geschrieben:Hum ok, so for the second part when you write the equation of equilibrium you say that T is equal to the sum of all elements in the two boxes?
Sorry about all these questions, but I am really confused :)
Yes I would do it like this (but i have no idea if this is correct either ;))
I think you can also say that T is the sum of the T's of each boxes the whole time, but for 0 ... 0.8C T_2 is 0.

Antworten

Zurück zu „Introduction to Biomechanics“